해커랭크1. Java If-Else submission

띠용,, 파이썬만 하다보니

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if문 조건문은 ()에 넣기 등등을 빼먹어서

괜히 시간 쓴 문제ㅠㅠ

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In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia

Task
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of 2 to 5, print Not Weird
• If  is even and in the inclusive range of 6 to 20, print Weird
• If  is even and greater than 20, print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

• 1 <= n <= 100

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풀이>

주어진 알고리즘대로 if A Then B, Else C 구조로 가야하기 때문에 다음과 같이 풀었다.

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

/*
If  is odd, print Weird
If  is even and in the inclusive range of  2to5 , print Not Weird
If  is even and in the inclusive range of  6to20 , print Weird
If  is even and greater than 20, print Not Weird
*/
    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        
        if (N%2 == 0 && (N>=2 && N<=5 || N>20)){
                System.out.println("Not Weird");
                
        }else{
            System.out.println("Weird");
            
        }
        
        scanner.close();
    }
}